백준/백준-C++
10820번: 문자열 분석
Beabletoet
2017. 6. 6. 00:21
#include<cstdio>
#include<iostream>
#include<string>
using namespace std;
int main()
{
string text;
while (getline(cin, text))
{
int ans[4] = { 0,0,0,0 };
for (int i = 0; i < text.size(); ++i)
if (text[i] >= 'a' && text[i] <= 'z')
++ans[0];
else if (text[i] >= 'A' && text[i] <= 'Z')
++ans[1];
else if (text[i] >= '0' && text[i] <= '9')
++ans[2];
else
++ans[3];
printf("%d %d %d %d\n", ans[0], ans[1], ans[2], ans[3]);
}
}